Question

The circuit above has a current of 0.32 A coming out of the power supply. Resistors R1, R2, and R3 have resistances of 408 LaTeX: \OmegaΩ, 2,296 LaTeX: \OmegaΩ, and 3,309 LaTeX: \OmegaΩ respectively, what is the voltage of the power supply

Answer 1

Answer:

1924 volts

Step-by-step explanation:

From Ohm's Law:

Voltage  (V) = Current (I) x Resistance (R)

                V=   I R....................................................... (1)

I = 0.32 A

R₁ = 408 Ω

R₂ =  2,296Ω

R₃ =   3,309Ω

Total Resistance =   408 + 2296+3309

                            =   6,013‬Ω

Substituting into  (1), we have :

V= 0.32 x  6,013‬

 =  1,924.16‬ volts

 ≅ 1924 volts