Respuesta :

Answer:

[tex]\sqrt{87}[/tex]

Step-by-step explanation:

Let AB=16,BC=5,CD=x,DA=18

BC and DA are perpendicular to CD

Draw a line from B parallel to CD intersecting DA at E.

As BCDE is a rectangle(all angles of quadrilateral=90)

Therefore BE=CD=x and ED=BC=5(opposite sides are equal in a rectangle)

⇒AD=AE+ED

18=AE+5

AE=13

⇒ By Pythogores theorem in right angled triangle ABE

[tex]AB^{2} =BE^{2} +EA^{2}[/tex]

[tex]16^{2} =x^{2} +13^{2} [/tex]

[tex]x^{2} =256-169[/tex]

x=[tex]\sqrt{87}[/tex]

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