Answer:
The P-value is 0.01.
The null hypothesis is rejected.
Step-by-step explanation:
If [tex]H_a: \mu>0.5[/tex], then the null hypothesis is [tex]H_0: \mu\leq0.5[/tex].
The significance level is 0.01.
The size of the sample is 26, so the degrees of freedom are 26-1=25.
[tex]df=n-1=26-1=25[/tex]
The test statistic is T=2.485.
The P-value, for T=2.485 and df=25, can be looked up in a t-table.
The P-value is 0.01.
As the P-value is equal to the significance level, the effect is considered significant and the null hypothesis is rejected.