Answer:
There is evidence at 95% level to support the claim that he average sodium content for a single serving of such a cereal is greater than 220 milligrams
Step-by-step explanation:
Create hypothesis as
[tex]H_0: \bar x =220 mg\\H_a: \bar x >220 mg/[/tex]
(Right tailed test at 5% significance level)
Mean difference = [tex]244-220 = 24mg[/tex]
STd error = [tex]\frac{s}{\sqrt{n} } \\=\frac{24.4}{\sqrt{20} } \\=5.46[/tex]
df =19
Test statistic t = mean diff/std error = 4.399
p value =0.0000155
Since p value is <0.05 reject null hypothesis.
There is evidence at 95% level to support the claim that he average sodium content for a single serving of such a cereal is greater than 220 milligrams