Answer:
B. W is positive and a is negative
Explanation:
As we know that the angular speed of the second clock is in positive direction so as it comes to halt from its initial direction of motion then we have
initial angular velocity is termed as positive angular velocity
[tex]\omega = positive[/tex]
now it comes to stop so angular acceleration is taken in opposite to the direction of angular speed
so we will have
[tex]\alpha = negative[/tex]
so here correct answer is
B. W is positive and a is negative