Answer: They should sample at-least 385 boxes of cereal .
Step-by-step explanation:
Let p be the proportion of boxes of cereal contain insect parts.
Given : The FDA would like to know that proportion to within 5 percentage points with 95% confidence.
i.e. margin of error : E= 0.05
We know that the z-value for 95% confidence = [tex]z_c=1.96[/tex]
Since the prior proportion of boxes of cereal contain insect parts is unknown , so we assume p = 0.5
Formula to find the sample size :
[tex]n=p(1-p)(\dfrac{z_{c}}{E})^2[/tex]
[tex]\Rightarrow\ n=0.5(1-0.5)(\dfrac{1.96}{0.05})^2[/tex]
Simply , we get
[tex]n=384.16\approx385[/tex]
Hence, they should sample at-least 385 boxes of cereal .