Question

Triangle ABC is translated on the coordinate plane below to create triangle A'B'C'.

If parallelogram EFGH is translated according to the same rule that translated triangle ABC, what is the ordered pair of point H'?

(-3, -3)

(4, 9)

(7, 6)

(0, -5)

Answer 1

As ypu can see, point A is moved by [3, 6], so point H=(1, 3) would turn into H'=(1, 3)+[3, 6]=(4, 9).

Answer 2

Step 1

Find the rule of the translation

we know that

$A(-1,-2) \\A'(-4,4)$

so

the rule of the translation is

$(x,y)-----> (x+3,y+6)$

that means

the translation is $3$ units to the right and $6$ units up  

Step 2

Find the coordinates of the ordered pair of point H'

$H(1,3)$

Applying the rule of the translation

$H(x,y)----->H'(x+3,y+6)$

$H(1,3)----->H'(1+3,3+6)$

$H(1,3)----->H'(4,9)$

therefore

the answer is

$H'(4,9)$