Respuesta :
The path of the car and the limo are straight lines.
To determine the equation of the lines of the paths, the slopes must be determined.
Let m1 = slope of car
m2 = slope of limo
so,
m1 = (7 + 7)/(5 + 2) = 2
m2 = (-5 -9)/(3+4) = -2
therefore the equations are
car:
2x – y = 2(5) –(7)
2x – y = 3
Limo:
2x + y = 2(3) – 5
2x + y = 1
Solving the intersection of the equations (using a calculator)
x = 1
y = -1
Answer:
(1,-1)
Step-by-step explanation:
Given,
The starting point of the car is (5,7) and end point of the car is (-2,-7),
So, the equation that represents the position of car,
[tex]y-7=\frac{-7-7}{-2-5}(x-5)[/tex]
[tex]y-7=\frac{-14}{-7}(x-5)[/tex]
[tex]y-7=2(x-5)[/tex]
[tex]y-7=2x-10[/tex]
[tex]\implies 2x-y=3-----(1)[/tex]
Similarly, the start point of the limo is (3,-5) and end point of the limo is (-4,9),
So, the equation that represents the position of limo,
[tex]y+5=\frac{9+5}{-4-3}(x-3)[/tex]
[tex]y+5=\frac{14}{-7}(x-3)[/tex]
[tex]y+5=-2(x-3)[/tex]
[tex]y+5=-2x+6[/tex]
[tex]2x+y=1----(2)[/tex]
Adding equation (1) and (2),
4x = 4 ⇒ x = 1
From equation (1),
2(1) - y = 3 ⇒ -y = 3 - 2 ⇒ -y = 1 ⇒ y = -1
Hence, the intersection point of line (1) and (2) is (1,-1).