The sum of two numbers is 13. Two times the first number minus three times the second number is 1. If you let x stand for the first number and y for the second number, what are the two numbers?
x+y= 13 2x-3y= 1 This can be found by using a system but I will try this method: x=13-y We replace it on the second one: 2(13-y) + y = 13 26-2y + y=13 -y= -13 y= 13
