Question

1.Complete the table. f(x) = e^(-x)

2. Use log 2 = a, log 3 = b to evaluate log (12).

Answer 1

Answer:

f(-3) = 20.08

f(3) = 0.049

log 12 = 2a + b

Step-by-step explanation:

1. Given that $f(x) = e^{-x}$

Therefore, $f(-3)=e^{-(-3)} = e^{3} = 20.08$

Again, $f(3) = e^{-3}=0.049$

2. $\log 12= \log (4 \times 3)= \log 4 + \log 3 = \log 2^{2} +\log 3 = 2\log 2 +\log 3$ {Since log ab =log a + log b and log a² = 2 log a}

So, $\log 12 = 2a+b$ {Since log 2 =a and log 3 = b given}