Given:
64.82 g of aluminum
metal
100.0oC is cooled
to 82.0 °C
specific heat of
aluminum is 0.897 J /g °C.
Required:
Change in heat
energy
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heat
of the water is 4.18 J/g-K
Plugging in the
values into the equation
H = mCpT
H = (64.82) (0.897
J /g °C) (82 – 100)
H = -1,046.6 J
