Answer:
This distribution has mean=0.75, standard deviation=0.0433 and approximately normal.
Step-by-step explanation:
We need to estimate the mean, standard deviation and shape of the distribution of the values of the sample proportions (p-hat) in repeated samples of size n=100.
The sample mean is expected to be the same as the population mean
[tex]\bar{p}=0.75[/tex]
The standard deviation can be calculated as:
[tex]\sigma=\sqrt{\frac{p*(1-p)}{n} } =\sqrt{\frac{0.75*(1-0.75)}{100} }= 0.0433[/tex]
The distribution is symmetrical, and it looks like approximately normal for this sample size.
So we can conclude this distribution has mean=0.75, standard deviation=0.0433 and approximately normal.