Respuesta :
Answer:
Step-by-step explanation:
Given
Fireplace is in the form of semi-ellipse with height of 3 ft from center
Length of base=8 ft
if the arch is in the form of ellipse then it can be considered as horizontal ellipse with 2 a and 2 b be length of major and minor axis
2 a =8
a=4 ft
If contractor cover the whole base
then total length of string=2a =8 ft
(b)String should be nailed at focus
focus of ellipse is a e
where e=eccentricity
[tex]e=\sqrt{1-(\frac{b}{a})^2}[/tex]
[tex]e=\sqrt{1-(\frac{3}{4})^2}=\frac{\sqrt{7}}{4}[/tex]
Focus [tex]=ae =\sqrt{7}[/tex]
Thus string should be nailed at 2.64 m from center
The distance between two points is the number of units between them.
- The total string length is 8ft
- The string should be positioned at a distance of [tex]\mathbf{\sqrt 7}[/tex] from the center
The given parameters are:
[tex]\mathbf{h= 3}[/tex]
[tex]\mathbf{w= 8}[/tex]
(a) The total string length
The total string length is the length along the base.
Hence, the total string length is 8ft
(b) How far from the center should the string be nailed
The position of the string should be at the focus (f).
This is calculated as:
[tex]\mathbf{f =ae}[/tex]
Where:
[tex]\mathbf{a = \frac 12 \times 8 = 4}[/tex] ---- 1/2 the length of the string
[tex]\mathbf{e = \sqrt{1 - (\frac ba)^2}}[/tex] ---- eccentricity
Where
[tex]\mathbf{b = h = 3}[/tex]
So, we have:
[tex]\mathbf{e = \sqrt{1 - (\frac{3}{4})^2}}[/tex]
[tex]\mathbf{e = \sqrt{1 - \frac{9}{16}}}[/tex]
[tex]\mathbf{e = \sqrt{ \frac{7}{16}}}[/tex]
So, we have:
[tex]\mathbf{e = \frac{\sqrt 7}{4}}[/tex]
The focus is then calculated as:
[tex]\mathbf{f = 4 \times \frac{\sqrt 7}{4} }[/tex]
[tex]\mathbf{f = \sqrt 7}[/tex]
Hence, the string should be positioned at a distance of [tex]\mathbf{\sqrt 7}[/tex] from the center.
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