Answer:
a) [tex]\bar{x}[/tex]=4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9
Step-by-step explanation:
a)
Mean
[tex]a)\bar{x}=\frac{1.9+ 2.3+ 5.7+ 5.2+ 1.9+ 8.8+ 3.9+ 7.3}{8} =\frac{37}{8}=4.625=\approx 4.63[/tex]
For the Median, we have to order the entries. So, ordering it goes:
1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8
Since we have even entries [tex]\frac{\frac{n}{2}+\frac{n}{2} +1}{2}=\frac{4th+5th}{2}=\frac{3.9+5.2}{2}=4.55[/tex]
mode
The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9
b)
Sample Standard Deviation
Here it is the formula to calculate it:
[tex]_{x}=\sqrt{\frac{\sum (x_{i}-\bar{x})^{2}}{n-1}}\\ S_{x}=\sqrt{\frac{46.855}{7}}\approx 2.58[/tex]
Coefficient of Variation
CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.
[tex]CV=\frac{S_x}{\bar{x}}*100%=\frac{2.58}{4.63} \approx 55.72%[/tex]
Range
The difference between the highest and the lowest value of this sample
8.8-1.9=6.9