On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 31 N31 N . The merry‑go‑round measures 8.5 m8.5 m from the axis of rotation to the edge where Bonnie applies her force. Assuming she applies her force perpendicularly to a line drawn from the axis of rotation, what is the magnitude of the torque ????τ Bonnie imparts to the merry‑go‑round?

Respuesta :

Answer:

The magnitude of the torque is 263.5 N.

Explanation:

Given that,

Applied force = 31 N

Distance from the axis = 8.5 m

She applies her force perpendicularly to a line drawn from the axis of rotation

So, The angle is 90°

We need to calculate the torque

Using formula of torque

[tex]\tau=Fd\sin\theta[/tex]

Where, F = force

d = distance

Put the value into the formula

[tex]\tau=31\times8.5\sin90[/tex]

[tex]\tau= 263.5\ N[/tex]

Hence, The magnitude of the torque is 263.5 N.

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