Question

In a laboratory, a student makes a solution by completely dissolving 80.0 grams of KNO3(s) in 100.0 grams of hot water. The resulting solution has a temperature of 60.°C. The room temperature in the laboratory is 22°C.

Classify, in terms of saturation, the type of solution made by the student.

Answer 1

Answer: Unsaturated

Explanation: There are three types of saturation levels that can be chosen, unsaturated, saturated, and supersaturated. If you look on Table G on the Reference Table, find the temperature in which the solution is at and go up until you reach the amount of dissolved substance (grams). If the dot is over the line then it is supersaturated, if its on the line then its saturated, and if it's below the line then is unsaturated. 
                                                                                        Cheers!

Answer 2

Answer:

Unsaturated solution.

Explanation:

At 60°C, 100.0g of water can dissolve 110g of KNO₃.

By definition, if you add 110g of KNO₃, the solution will be saturated, if you add more than 110g, the solution becomes supersaturated (That means crystals of solute will form), if you add less than 110g, the solution is unsaturated.

In the problem, you are adding 80g of KNO₃(s), that means you made a unsaturated solution.