Answer:
[tex]\large{\textbf{x = 0, 3}\\}[/tex]
Step-by-step explanation:
[tex]\large{\textup{Given}:\\$5x^2 = 15x$\\$\implies 5x^2 - 15x = 0$\\\textup{Taking $x$ common outside, we get:}\\$x\{5x - 15 \} = 0$\\\textup{Then we have two possibilities for $x $}\\$i.e., x = 0$ \hspace{5mm} \textup{or} \hspace{5mm} $5x - 15 = 0 \implies x = 3$\\$\therefore x = 0, 3 $}[/tex]
