Answer:[tex]2.55 rad/s^2[/tex] ccw
Explanation:
Given
[tex]N_1=5.91 rpm[/tex] (ccw)
[tex]\omega _1=2\pi 3.17\cdot 5.91=37.13 rad/s[/tex] (cw)
t=22.3 s
[tex]N_2=3.17 rpm[/tex] (cw)
[tex]\omega _2=2\pi 3.17\cdot 3.17=19.92 rad/s[/tex] (cw)
[tex]\omega _2=\omega _1+\alpha \cdot t[/tex]
where [tex]\alpha [/tex]is the angular acceleration
[tex]-19.92=37.13+\alpha \cdot 22.3[/tex]
[tex]\alpha =-2.55 rad/s^2[/tex]