bearing in mind that parallel lines have the same exact slope, then any parallel line to the one above will have the same slope as that one.
[tex]\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \qquad \implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{3}}x-4[/tex]
