Question

A vanadium bolt gives up 1124 J of energy as its temperature drops 25 k if the bolts mass is 93 g what is its specific heat

Answer 1

Answer:

0.483 J/(gK)

Explanation:

When a sample of a material of mass m gives off an amount of energy Q, the temperature of the material decreases by $\Delta T$, according to the equation :

$Q=mC_s \Delta T$

where  $C_s$ is the specific heat capacity of the material.

In this problem, we have:

m = 93 g is the mass of the vanadium bolt

$Q = -1124 J$ is the amount of energy given off by the vanadium bolt

$\Delta T = -25 K$ is the change in temperature of the vanadium

Solving the equation for $C_s$, we find the specific heat capacity of vanadium:

$C_s = \frac{Q}{m \Delta T}=\frac{-1124}{(93.0)(-25)}=0.483 J/(gK)$