Answer:
[tex]\large{\textbf{f(g(x)) = 20}\\}[/tex]
Step-by-step explanation:
[tex]\large{\textup{Given}:\\$f(x) = 5x $ \hspace{5mm} \& \hspace{5mm} $g(x) = 4x $\\$ f \circ g(x) = f(g(x)) $\\$ \implies f(g(x)) = f(5x) $\\\textup{i.e., To substitute $5x$ instead of $x$ in $f(x)$}\\$\implies f(5(x)) = 4(5(x)) = 20x \\ $\textup{Now,}$f(g(1)) = 20(1) =20$}[/tex]