Answer:
By the elimination method, solving the equation we get x =-1, y = 7/5
Explanation:
Let [tex]\frac{1}{5} x+y=\frac{6}{5}[/tex] be equation 1.
Solving the equation, we get x+5 y=6 as equation 1
Similarly for equation 2, [tex]\frac{1}{10} x+\frac{1}{3} y=\frac{7}{10}[/tex]
we get, 3x + 10y = 21 as equation 2
Solving both equation,
Multiplying equation 1 by 3
[tex]3 x+15 y=18[/tex]
[tex]3 x+10 y=21[/tex]
and subtracting both the equations
We get [tex]5y = 7; y = 7/5[/tex]
Substituting the value of y in equation 1, we get [tex]x + 5(7/5) = 6[/tex]
[tex]x+7=6[/tex]
[tex]x = 6-7 = -1[/tex]