Answer:
E) 0.977
Explanation:
From the question we have that the mean number of transactions is 478 and standard deviation is 64.
[tex]\implies \mu=478[/tex] and [tex]\sigma=478[/tex]
We want to find the proportion of daily transaction that is greater than 350 i.e [tex]P(X\:>\:350)[/tex]
We first find the z-score using the formula:
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{350-478}{64}=-2[/tex]
Reading from the standard normal distribution table [tex]P(X\:<\:350)=0.0228[/tex]
Note that:
[tex]P(X\:>\:350)=1-P(X\:<\:350)[/tex]
[tex]\implies P(X\:>\:350)=1-0.0228=0.9772[/tex]
Therefore the proportion of daily transactions greater than 350 is 0.977
The last option is correct