Answer:
The slop of line perpendicular to line y = [tex]\frac{1}{3}[/tex] x - 2 is ( - 3)
Step-by-step explanation:
Given Line equation as ,
y = [tex]\frac{1}{3}[/tex] x - 2
The equation of line is y = mx + c
Slop of this line (m1) = [tex]\frac{1}{3}[/tex]
Now second line with slop (m2) is perpendicular to line first , then
(m1) × (m2) = - 1
So, (m2) =[tex]\frac{-1}{m1}[/tex]
Or , (m2) = [tex]\frac{-1}{\frac{1}{3}}[/tex]
∴ (m2) = - 3
Hence the slop of line perpendicular to line y = [tex]\frac{1}{3}[/tex] x - 2 is ( - 3) Answer
