Answer:
A. 20 m/s north
Explanation:
The velocity of the car can be calculated as:
[tex]v=\frac{d}{t}[/tex]
where
d is the displacement
t is the time interval
Taking north as positive direction, the initial position of the car is
[tex]r_i = -50 m[/tex] (south)
while the final position is
[tex]r_f = +250 m[/tex] (north)
So, the displacement is
[tex]d=r_f -r_i = +250-(-50)=+300 m[/tex] (north)
The time interval for the motion is
t = 15 s
So, the velocity of the car is
[tex]v=\frac{+300}{15}=+20 m/s[/tex] (north)