Question

Three zeroes of a fifth degree polynomial function are 1/3,4-6i, and -2+11i . Determine the
remaining zeroes of the function.
4+6i, -2-11i
-1/3, 4+6i, 2+11i
-4+6i, 2-11i
3, 4+6i, -2-11i

Answer 1

If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.

So, if 4-6i is a zero, 4+6i will be a zero as well

If -2+11i is a zero, -2-11i will be a zero as well

So, the zeroes are

$\dfrac{1}{3},\ 4-6i,\ 4+6i,\ -2+11i,\ -2-11i$

Answer 2

Answer:

Step-by-step explanation:

As the other helper has pointed out, the imaginary zeros occur in pairs. So the other two zeroes are 4+6i and -2-11i.

Here are some answers of your Chemistry questions:

1. How many valence electrons does a helium atom have? (1 point)

2

2. What is the formula of the ion formed when potassium achieves noble-gas electron configuration? (1 point)

K+

3. How does oxygen obey the octet rule when reacting to form compounds? (1 point)

It gains electrons.

4. What is the basis of a metallic bond? (1 point)

the attraction of metal ions to mobile electrons

5. An ionic bond is a bond between ____. (1 point)

a cation and an anion