Answer:
(x-i)(x+i)
Step-by-step explanation:
first, put the equation equal to 0:
[tex] {x}^{2} + 1 = 0[/tex]
then get the x term alone on one side:
[tex] {x}^{2} = - 1[/tex]
next, do the inverse operation to clean up the x term side, since x is to the 2nd power, we find the second (square) root of both sides:
[tex] \sqrt{x^{2} } = \sqrt{ - 1} [/tex]
Simplify:
[tex]x = i \: or \: x = - i[/tex]
Add/subtract the imaginary numbers to bring them with the x term again.
[tex](x - i)(x + i) = 0[/tex]
For this problem, you can just drop the "=0" part now that it's factored:
[tex](x - i)(x + i)[/tex]