13. In triangle MNP, if
measure M = 4x - 3, measure N = 9x - 6, and measure P = 6x - 1, find x and the measure of each angle.​

Respuesta :

Answer:

Part a) [tex]x=10[/tex]

Part b) m∠M=37°, m∠N=84°, m∠P=59°

Step-by-step explanation:

Part a) Find out the measure of each angle

we know that

The sum of the internal angles in a triangle must be equal to 180 degrees

In this problem

m∠M+m∠N+m∠P=180°

substitute the given values

[tex](4x-3)\°+(9x-6)\°+(6x-1)\°=180\°[/tex]

Solve for x

Combine like terms

[tex]19x-10=180[/tex]

Adds 10 both sides

[tex]19x=180+10[/tex]

[tex]19x=190[/tex]

Divide by 19 both sides

[tex]x=10[/tex]

Part b) Find the measure of each angle

1) m∠M=(4x-3)°

substitute the value of x

m∠M=(4(10)-3)=37°

2) m∠N=(9x-6)°

substitute the value of x

m∠N=(9(10)-6)=84°

3) m∠P=(6x-1)°

substitute the value of x

m∠P=(6(10)-1)=59°

Angles in a triangle add up to 180 degrees.

The value of x is 10, and the measures of the angles are 37. 59 and 84 degrees

The given parameters are:

[tex]\mathbf{M = 4x - 3}[/tex]

[tex]\mathbf{N = 9x - 6}[/tex]

[tex]\mathbf{P = 6x - 1}[/tex]

So, we have:

[tex]\mathbf{M + N + P = 180}[/tex]

Substitute known values

[tex]\mathbf{4x - 3 + 9x - 6 + 6x -1 = 180}[/tex]

Collect like terms

[tex]\mathbf{4x + 9x + 6x = 180 + 1 + 6 + 3}[/tex]

[tex]\mathbf{19x = 190}[/tex]

Divide both sides by 19

[tex]\mathbf{x = 10}[/tex]

So, we have:

[tex]\mathbf{M = 4(10) - 3 = 37}[/tex]

[tex]\mathbf{N = 9(10) - 6 = 84}[/tex]

[tex]\mathbf{P = 6(10) - 1 = 59}[/tex]

Hence, the value of x is 10, and the measures of the angles are 37. 59 and 84 degrees

Read more about triangles at:

https://brainly.com/question/2773823

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