The smiths have two children. The sum of their ages is 23. The produce of their ages is 132. How old are the children?

Respuesta :

For this case we propose a system of equations:

x: Let the variable representing the age of the first child of the Smiths

y: Let the variable representing the age of the second child of the Smiths

According to the data of the statement we have to:

[tex]x + y = 23\\x * y = 132[/tex]

From the first equation we have to:

[tex]x = 23-y[/tex]

We substitute in the second equation:

[tex](23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0[/tex]

We find the solutions by factoring:

We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.

Thus, we have that the factorized equation is:

[tex](y-11) (y-12) = 0[/tex]

Thus, the solutions are:[tex]y_ {1} = 11\\y_ {2} = 12[/tex]

So, we can take any of the solutions:

With [tex]y = 11[/tex]

Then[tex]x = 23-11 = 12[/tex]

Therefore, the ages of the children are 11 and 12 respectively.

Answer:

 The ages of the children are 11 and 12 respectively.

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