Answer:
17.21kW and 13.97kW
Explanation:
To solve this question we have two data that are provided to us and correspond to the Enthalpy.
[tex]h1=239.16kJ/kg\\h2=296.81kJ/kg[/tex]
The energy in mass and enthalpy terms is given by.
[tex]E_{mass,in}=mh_1[/tex]
Where the variables are,
We only proceed to replace the values.
[tex]E_{mass,in}=(0.058Kg/s)(239.16kJ/kg)\\E_{mass,in}=12.91kW[/tex]
Energy transfer rate by mass in the compressor is 13.97kW
Being analogs for the other part of the cycle,
[tex]E_{mass,out}=mh_2[/tex]
Substituing,
[tex]E_{mass,out}=(0.058Kg/s)(296.81kJ/kg)\\E_{mass,out}=16.02kW[/tex]
Energy transfer rate by mass out of the compressor is 17.21 kW