Respuesta :
Answer:
power developed by the turbine = 6927.415 kW
Explanation:
given data
pressure = 4 MPa
specific enthalpy h1 = 3015.4 kJ/kg
velocity v1 = 10 m/s
pressure = 0.07 MPa
specific enthalpy h2 = 2431.7 kJ/kg
velocity v2 = 90 m/s
mass flow rate = 11.95 kg/s
solution
we apply here thermodynamic equation that
energy equation that is
[tex]h1 + \frac{v1}{2} + q = h2 + \frac{v2}{2} + w[/tex]
put here value with
turbine is insulated so q = 0
so here
[tex]3015.4 *1000 + \frac{10^2}{2} = 2431.7 * 1000 + \frac{90^2}{2} + w[/tex]
solve we get
w = 579700 J/kg = 579.7 kJ/kg
and
W = mass flow rate × w
W = 11.95 × 579.7
W = 6927.415 kW
power developed by the turbine = 6927.415 kW
The power developed by the turbine will be 6927,415 kW.
We can arrive at this answer through the following calculation:
- Use the thermodynamic equation:
[tex]h1+\frac{v1}{2} +q=h2+\frac{v2}{2} +w[/tex]
- Considering that [tex]q=0[/tex] we can solve the equation as follows:
[tex]3015.4*1000+\frac{10^2}{2}=2431.7*1000+\frac{90^2}{2}+w\\3015400+\frac{10^2}{2}=2431700+\frac{90^2}{2}+w\\w=579.7 kJ/kg[/tex]
- Then we can use this value to find the value of W, which is the power developed by the turbine. This will be done as follows:
[tex]W=mass flow rate×w\\W = 11.95 × 579.7\\W = 6927.415 kW[/tex]
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