Question

2. Find the empirical formula for a compound which contains 32.8% chromium and 67.2%
chlorine.

Answer 1

The empirical formula is CrCl₃.

Explanation:

To find the empirical formula we use the following algorithm.

We divide each percentage by the atomic weight of each element:

for Cr   32.8 / 52 = 0.63

for Cl   67.2 / 35.5 = 1.89

The result will be divined by the smallest number:

for Cr    0.63 / 0.63 = 1

for Cl     1.89 / 0.63 = 3

The empirical formula is CrCl₃.

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