Answer:
Impulse in the first collision is greater
Explanation:
u = Initial velocity of cart
v = Final velocity of cart
m = Mass of of cart
First collision
Impulse
[tex]J=m(v-u)\\\Rightarrow J=m(0.3-(-0.3))\\\Rightarrow J=m(0.6)[/tex]
Second collision
Impulse
[tex]J=m(v-u)\\\Rightarrow J=m(0-(-0.3))\\\Rightarrow J=m(0.3)[/tex]
Hence, the impulse in the first collision is greater than the second impact