If the voltage across a circuit of constant resistance is doubled, how is the current in the circuit affected?
(a)-The current is quadrupled.
(b)-The current is reduced by a factor of 2.
(c)-The current is reduced by a factor of 4.
(d)-The current remains constant.
(e)-The current is doubled.

Respuesta :

Answer:

(e)-The current is doubled.

Explanation:

According to Ohm law, [tex] I = \frac{V}{R}[/tex] where I is the current, V is the voltage and R is the resistant.

[tex]I_1 = \frac{V_1}{R_1}[/tex]

[tex]I_2 = \frac{V_2}{R_2}[/tex]

If V is doubled, [tex] V_2 = 2V_1[/tex] while R remains constant [tex]R_2 = R_1[/tex] we would have

[tex]I_2 = \frac{2V_1}{R_1} = 2(\frac{V_1}{R_1}) = 2I_1 [/tex]

The current is doubled.

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