Question

Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106M O2, 0.00652M SO3, and 0.00129M SO2. Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106 M O2, 0.00652 M SO3, and 0.00129 M SO2.
2 SO3 (g) ⇌ 2 SO2 (g)+O2(g)

(a)1.34 × 10^-2
(b)6.78 × 10^-2
(c)4.15 × 10^-3
(d)4.35 × 10^-2

Answer 1

equilibrium constant K = 4.15 × 10⁻³

Explanation:

We have the following chemical equilibrium:

2 SO₃ (g) ⇄ 2 SO₂ (g) + O₂ (g)

equilibrium constant K = ( [SO₂]² × [O₂] ) / [SO₃]²

equilibrium constant K = ( 0.00129² × 0.106 ) / 0.00652²

equilibrium constant K = 0.414 × 10⁻² = 4.14 × 10⁻³ ≈ 4.15 × 10⁻³

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