Question

A 750 kg dragster accelerates from rest to a final speed of 160 m/s in 500 m and encounters an average frictional force of 800 N. What is its average power output in watts if this takes 9.50 s?

Answer 1

Explanation:

Power = change in energy / change in time

P = (KE + W) / t

P = (½ mv² + Fd) / t

P = (½ (750 kg) (160 m/s)² + (800 N) (500 m)) / (9.50 s)

P = 1.05×10⁶ W