Question

In the isosceles triangle below the congruent side each measure 13 meter if the bases of the triangle is 10 what is the height of the triangle

Answer 1

Answer:

The Height of isosceles Triangle = 12 meter

Step-by-step explanation:

Given as ,

A isosceles triangle each sides measure = 13 meter

Base of triangle = 10 meter

Let the height of triangle = H

Now Height (H) = $\sqrt{ a^2-{\frac{b^2}{4}}}$

where B = base  = 10 m

And     a= sides = 13 m

So , H = $\sqrt{ a^2-{\frac{b^2}{4}}}$

      H = $\sqrt{ 13^2-{\frac{10^2}{4}}}$

      H = $\sqrt{144}$ = 12 meter

Hence , the Height of isosceles Triangle = 12 meter    Answer