Respuesta :

Answer:

[tex]x= \frac{-5+\sqrt{57} }{2}[/tex]

or, [tex]x= \frac{-5-\sqrt{57} }{2}[/tex]

Step-by-step explanation:

We are given a quadratic equation of single variable x which is [tex]x^{2} =-5x+8[/tex].

Now, we can write [tex]x^{2} +5x-8 =0[/tex] ...... (1)

We can not solve the equation by factorizing the left hand term.

Therefore, use Sridhar Acharya Formula to get the solution

The formula gives if [tex]ax^{2} +bx+c =0[/tex], then we can write

[tex]x= \frac{-b+ \sqrt{b^{2}-4 \times a \times c } }{2a}[/tex]

or [tex]x= \frac{-b- \sqrt{b^{2}-4 \times a \times c } }{2a}[/tex]

Therefore, for this case

[tex]x=\frac{-5+\sqrt{5^{2}-4 \times 1 \times (-8) } }{2}[/tex]

or, [tex]x=\frac{-5-\sqrt{5^{2}-4 \times 1 \times (-8) } }{2}[/tex]

⇒ [tex]x= \frac{-5+\sqrt{57} }{2}[/tex]

or, [tex]x= \frac{-5-\sqrt{57} }{2}[/tex] (Answer)

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