Answer:
[tex]x= \frac{-5+\sqrt{57} }{2}[/tex]
or, [tex]x= \frac{-5-\sqrt{57} }{2}[/tex]
Step-by-step explanation:
We are given a quadratic equation of single variable x which is [tex]x^{2} =-5x+8[/tex].
Now, we can write [tex]x^{2} +5x-8 =0[/tex] ...... (1)
We can not solve the equation by factorizing the left hand term.
Therefore, use Sridhar Acharya Formula to get the solution
The formula gives if [tex]ax^{2} +bx+c =0[/tex], then we can write
[tex]x= \frac{-b+ \sqrt{b^{2}-4 \times a \times c } }{2a}[/tex]
or [tex]x= \frac{-b- \sqrt{b^{2}-4 \times a \times c } }{2a}[/tex]
Therefore, for this case
[tex]x=\frac{-5+\sqrt{5^{2}-4 \times 1 \times (-8) } }{2}[/tex]
or, [tex]x=\frac{-5-\sqrt{5^{2}-4 \times 1 \times (-8) } }{2}[/tex]
⇒ [tex]x= \frac{-5+\sqrt{57} }{2}[/tex]
or, [tex]x= \frac{-5-\sqrt{57} }{2}[/tex] (Answer)