Answer:
See below in bold.
Step-by-step explanation:
Rewrite the function and integrate term by term:
= ∫ [ (6v - 2) / 2(3v^2 - 2v - 1) - 3 / (3v^2 - 2v - 1) ]
= 1/2 ∫ (6v - 2) / (3v^2 - 2v - 1) - 3 ∫ 1 / (3v^2 - 2v - 1)
= 1/2 ∫ (6v - 2) / (3v + 1(v - 1) - 3 ∫ 1 / (3v + 1)(v - 1)
= 5/4 ln (3v + 1) - 1/4 ln (1 - v) + C.
