Respuesta :
Answer:
24
The problem:
If [tex]\frac{1}{2}x+\frac{1}{3}y=4[/tex], what is the value of [tex]3x+2y[/tex]?
Explanation:
[tex]\frac{1}{2}x+\frac{1}{3}y=4[/tex]
I would like to clear the fractions.
You can do this by multiplying both sides by a common multiple of your denominators; preferably the least common multiple.
So the least common multiple of 2 and 3 is 6.
So I'm going to multiply both sides by 6:
[tex]6(\frac{1}{2}x+\frac{1}{3}y)=6(4)[/tex]
Distribute and multiply:
[tex]\frac{6(1)}{2}x+\frac{6(1)}{3}y=24[/tex]
[tex]\frac{6}{2}x+\frac{6}{3}y=24[/tex]
[tex]3x+2y=24[/tex]
So the value of [tex]3x+2y[/tex] with the given condition is 24.
The value of 3x + 2y will be 24
From the information given, the equation is 1/2x + 1/3y = 4. In this case, the first thing to do is to clear the fraction, this will be done by multiplying the fraction by the lowest common multiple which is 6. This will be:
6(1/2x + 1/3y) = 6(4)
3x + 2y = 24
Therefore, since the question is for us to calculate the value of 3x + 2y, the calculation above had indicated that the value will be 24.
In conclusion, the value of 3x + 2y is 24
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