Answer:
Step-by-step explanation:
To find the value of x² + (2y) ÷(2w) +3z , first we substitute the values of w, x, y and z
5² + 2(8) ÷ 2(2) + 3(3)
To simplify this further, we have to apply the rule of BODMAS
(Applying the rule of BODMAS simply means when you have an equation, if its having bracket, you have to remove the bracket first, then you move to powers then you proceed to dividing then subtraction and then addition)
5² + 2(8) ÷ 2(2) + 3(3)
=25 +16 ÷ 4 +9
=25 + 4 +9
=38
Therefore the value of x² + (2y) ÷(2w) +3z is 38
The given expression has some variables and their values are also given in the question, so using the substitution method,
The value of [tex]x^2+(2y/2w)+3z[/tex] is 38.
Given information:
The expression [tex]x^2+(2y/2w)+3z[/tex]
where,
The value of x = 5,
The value of w = 2,
The value of y = 8,
And
The value of z = 3.
On putting the given values in the given expression and solving for the final answer as,
[tex]x^2+(2y/2w)+3z[/tex]
[tex]=5^2+\frac{2\times 8}{2\times2} +3\times3\\=25+4+9\\=38[/tex]
Hence ,by using the substitution method the value of [tex]x^2+(2y/2w)+3z[/tex] is 38.
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https://brainly.com/question/14619835
