Question

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative 6 plus or minus StartRoot (negative 6) squared minus 4 (9)(1) EndRoot Over 2(9) EndFraction
x = StartFraction negative 6 plus or minus StartRoot 36 minus 36 EndRoot Over 18 EndFraction
x =

Answer 1

Answer:

x = -1/3

Step-by-step explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

Answer 2

Answer:

$x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}$

Step-by-step explanation:

For this function [f(x)=9x²+6x+1], we'll solve it by the traditional way, via General Formula

$9x^{2}+6x+1=0 \Rightarrow x=\frac{-6\pm \sqrt{6^{2}-4(9)(1)}}{2*9}\Rightarrow x=-\frac{1}{3}\Rightarrow S=\left \{ -\frac{1}{3} \right \}$