jen1295
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NEED HELP ASAP !!!Six times the sum of two consecutive integers is eight more than five times the
larger integer. Find the integers.
The first integer is
The second integer is

Respuesta :

CPED

Answer:

The first integer is  1

The second integer is 2

Step-by-step explanation:

Given that two numbers are consecutive:

Let the integers be:

First integer = x

Second Integer = x +1

Now according to given conditions the equation will be:

  • Sum of two consecutive integers = x+ (x+1) = 2x +1
  • Six times the sum of two consecutive integers =6(2x + 1) = 12x + 6
  • Larger integer = x+1
  • five times the  larger integer = 5(x +1)= 5x + 5
  • eight more than five times the  larger integer= 5x +5 +8= 5x + 13

Final equation:

12x + 6 = 5x +13

Taking terms with x on left and others on right side

12x - 5x = 13 - 6       (signs of transferred terms will be changed)

7x = 7

Dividing both sides by 7 we get:

x = 1

So,

The first integer is  1

The second integer is 1+1 =2

I  hope it will help you!

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