Question

What is the standard form for the quadratic function? f( x ) = ( x − 3 )^2 + 5 f( x ) = x^2 +6x −4 f( x ) = x^2 −6x + 14 f( x ) = x^2 + 14 f( x ) = x^2 − 4 Thanks!

Answer 1

Answer:

$f(x)=x^2-6x+14$

Step-by-step explanation:

The given quadratic function is:

$f(x)=(x-3)^2+5$

We rewrite as:

$f(x)=(x-3)(x-3)+5$

We expand to get:

$f(x)=x^2-3x-3x+9+5$

Combine similar terms

$f(x)=x^2-6x+14$

This the standard form the given quadratic function.