Question

A 10.00 mL sample of vinegar, an aqueous solution of acetic acid (HC₂H₃O₂), is titrated with 0.5062M NaOH, and 16.58 mL is required to reach the endpoint. If the density of the vinegar is 1.006 g/mL, what is the molarity of the acetic acid in the solution? You may assume that acetic acid contains one acidic hydrogen.

Answer 1

Answer:

0.8393 M

Explanation:

Because acetic acid contains one acidic hydrogen, we can write the reaction as follows:

• HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

Then we use the formula C₁*V₁=C₂*V₂, in order to calculate the concentration of acetid acid in vinegar:

• C₁ * 10.00 mL = 0.5062 M * 16.58 mL

• C₁ = 0.8393 M

And that's it, no calculation using density is required to solve this problem.