Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes = [tex]1000\times 8 = 8000 bits[/tex]
Distance, d = 2500 km = [tex]2.5\times 10^{6}\ m[/tex]
Speed of propagation, s = [tex]2.5\times 10^{8}\ m/s[/tex]
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:
[tex]t = \frac{d}{s} = \frac{2.5\times 10^{6}}{2.5\times 10^{8}} = 0.01\ s[/tex]
t = 10 ms
[tex]t = \frac{link\ distance}{Propagation\ speed}[/tex]