Answer:
Temperature at which the resistance is twice the resistance at [tex]20^{\circ}C[/tex] is [tex]194.216^{\circ}C[/tex]
Solution:
As per the question:
Temperature coefficient, [tex]\alpha = 5.74\times 10^{- 3}^{\circ}C[/tex]
Reference temperature, [tex]T_{o} = 20^{\circ}C[/tex]
Resistance, [tex]R_{t} = 2R_{o}[/tex]
Now, using the formula:
[tex]R_{t} = R_{o}(1 + \alpha \Delta T)[/tex]
[tex]2R_{o} = R_{o}(1 + \alpha \times (T _ T_{o}))[/tex]
[tex]2 = 1 + 5.74\times 10^{- 3}\times (T - 20^{\circ})[/tex]
[tex]\frac{1}{5.74\times 10^{- 3}} = T - 20^{\circ}[/tex]
[tex]T = 174.216 + 20 = 194.216^{\circ}[/tex]