Answer:
The equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 is [tex]y+6=\frac{1}{3}(x+2)[/tex]
Solution:
Given that line passes through (-2, -6) and has slope of 1/3
We have to find the equation of the line
The point slope form is given as
[tex]y-b=m(x-a)[/tex]
where m is the slope of the line and a, b are the x, y coordinates of the given point through which the line passes.
Here in this question, m = 1/3 and a = -2 and b = -6
By substituting in point slope form we get,
[tex]y - (-6) = \frac{1}{3}(x - (-2))\\\\y + 6 = \frac{1}{3}(x + 2)[/tex]
Hence the equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 is [tex]y+6=\frac{1}{3}(x+2)[/tex]
