Question

Reduce the following equation to a net ionic equation: 2Na+ + SO4^2- + Ba^2+ + 2Cl^- ---> 2Na^+ + 2Cl^- + BaSOv4


A.) 2Na^+ + 2Cl^- ---> 2NaCl

B.) SOv4^2- + Ba^2+ ---> BaSOv4

C.) 2Na^+ + SO4^2- ---> Nav2SOv4


v= Sub

B.) on edg

Answer 1

net ionic equation

B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

Explanation:

We have the following chemical equation:

2 Na⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 Cl⁻ (aq) → 2 Na⁺ (aq) +  2 Cl⁻ (aq) + BaSO₄ (s)

To get the net ionic equation we remove the spectator ions and we get:

SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

were:

(aq) - aqueous

(s) - solid

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net ionic equation

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Answer 2

Answer:

B. SO4^2- + Ba^2+ >>> BaSO4

Explanation:

On edg