Question

what it the molarity of 125 ml of solution containing 5.31 g sodium nitrate​

Answer 1

molarity of the sodium nitrate solution = 0.496 ≈ 0.5 M

Explanation:

First we need to determine the number of moles of sodium nitrate (NaNO₃).

number of moles =  mass / molecular weight

number of moles of sodium nitrate = 5.31 / 85 = 0.062 moles

Now we determine the molarity of the solution with the following formula:

molarity = number of moles / solution volume (L)

molarity of the sodium nitrate solution = 0.062 / 0.125 = 0.496 ≈ 0.5 M

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